July 17, 2012

How to open a form by using AX code

How to open a form by using AX code

Hi Guys,

      Today we are going to open a form using code..just try following code

 if(inventtable.Family == family::MettalicCore)
   {
   new MenuFunction(MenuItemDisplayStr(Attributes1),MenuItemType::Display).run();
    }
    else
    {
     new MenuFunction(MenuItemDisplayStr(Attributes),MenuItemType::Display).run();
     }

Here we are opening a form of Attributes1 and Attributes form its a simple way.Block Super()

Here is another way take a look


static void OpenFormByCodeB()
{ FormRun formRun;
Args args = new Args();
;
args.name(formstr(CustTable));
args.record(CustTable::find('ABC'));

formRun = ClassFactory.formRunClass(args);
formRun.init();
formRun.run();
formRun.wait();
}


Now if we tweak this a little bit, we can add our code
Like this:


static void OpenFormByCodeB()
{ Object formRun;
Args args = new Args();
;
args.name(formstr(CustTable));
args.record(CustTable::find('ABC'));

formRun = ClassFactory.formRunClass(args);
formRun.init();

formRun.yourmethodgoeshere(); /* !!

formRun.run();
formRun.wait();
}

By changing the type of formRun from class FormRun to class Object, we can implement and execute extra methods on our destination form! This gives us extra possibilities for customizations. You can pass along extra parameters for example.
Only drawback: While programming, your method doesn't show up in the IntelliSense, showing all the available methods. So be carefull of typo's. 

-Harry

1 comment:

  1. Hi , i want to know the actual meaning of this piece of code

    args.name(formstr(CustTable));

    Can anyone tell me why we use this line and what is it exactly!!?

    ReplyDelete

Thanks

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